"submit suggest believe ".split() # ['submit', 'suggest', 'believe']
import re print(re.match("^[a-zA-Z]{2}.*$","ssss") is not None) # True
import re word = "china." if re.match("^.*[a-zA-Z]{1}$",word) is None: print(word[:-1])
counts = {} word = "suggest" counts[word] = counts.get(word, 0) + 1 print(counts) # {'suggest': 1}
counts = {"damage":2,"within":5} countsList = list(counts.items()) print(countsList) # [('damage', 2), ('within', 5)]
countsList = [("dynamic",3),("subject",5)] countsList.sort(key=lambda x:x[1], reverse=True)#排序 print(countsList) # [('subject', 5), ('dynamic', 3)]
不积跬步,无以至千里;不积小流,无以成江海。以上都是python基本操作知识点总结
import re rule1 = re.compile('^[a-zA-Z]{2}.*$') rule2 = re.compile('^.*[a-zA-Z]{1}$') excludes = ['the', 'of', 'to', 'and', 'in', 'a', 'is', 'were', 'was', 'you', 'I', 'he', 'his', 'there', 'those', 'she', 'her', 'their', 'that', '[a]', '[b]', '[c]', '[d]', 'them', 'or','for','as', 'are','on','it','be','with','by','have','from','not','they', 'more','but','an','at','we','has','can','this','your','which','will', 'one','should','points)','________','________.','all','than','what', 'people','if','been','its','new','our','would','part','may','some','i', 'who','answer','when','most','so','section','no','into','do','only', 'each','other','following','had','such','much','out','--','up','these', 'even','how','directions:','use','because','(10','time','(15','[d].', '-','it.','[b],','[a],','however,','1','c','1.','2.','b','d','a','(10', '2','12.','13.','29.','3.','4.','5.','6.','7.','8.','9.','10.','11.','14.', '15.','【答案】a','【答案】d','【答案】b','【答案】c','c)','b)','a)','d)', 'a),','b),','d).','c),'] #自行过滤简单词 def getTxt(): txt = open('vocabulary/EnglishText.txt').read() txt = txt.lower() for ch in '!"@#$%^&*()+,-./:;<=>?@[]_`~{|}': #替换特殊字符 txt.replace(ch, ' ') return txt #1.获取单词 EngTxt = getTxt() #2.切割为列表格式 txtArr = EngTxt.split() #3.遍历统计 counts = {} for word in txtArr: if word not in excludes and rule1.match(word) is not None : # print(rule2.match(word) is None,word) if rule2.match(word) is None: word = word[:-1] # print(rule2.match(word) is None,word) counts[word] = counts.get(word, 0) + 1 #4.转换格式，方便打印，将字典转换为列表 countsList = list(counts.items()) countsList.sort(key=lambda x:x[1], reverse=True)#排序 print(len(countsList)) #5.打印 for word,count in countsList: with open('vocabulary/output_1.txt','a+') as f: str1=word+' : '+str(count)+ '次' f.writelines('<li>{0:15} - {1:10} </li>\n'.format(word,count)) f.close() print('<li>{0:15} - {1:10} </li>'.format(word,count))