The zip() function takes iterables (can be zero or more), aggregates them in a tuple, and returns it.
zip()
languages = ['Java', 'Python', 'JavaScript'] versions = [14, 3, 6] result = zip(languages, versions) print(list(result)) print(dict(result))
# lambda that accepts one argument greet_user = lambda name : print('Hey there,', name) # lambda call greet_user('Delilah')
mylist = [(3, 5, 8), (6, 2, 8), (2, 9, 4), (6, 8, 5)] sorted(mylist, key=lambda x: x[1])
def factorial(x): """This is a recursive function to find the factorial of an integer""" print(x) if x == 1: return 1 else: return (x * factorial(x-1)) factorial(3)
3 2 1
dict1 = {'abundance':60, 'name':'c1', 'child':[ { 'abundance':5, 'name':'cc1', 'child': [ { 'abundance':2, 'name':'ccc1', 'child':[] }, { 'abundance':2, 'name':'ccc1', 'child':[] } ] }, { 'name':'cc1', 'abundance':6, 'child':[] } ] } def compute_abundance(d): sum_ab = sum([compute_abundance(c) for c in d['child']]) print(d['name'],sum_ab) return d['abundance'] compute_abundance(dict1)
ccc1 0 ccc1 0 cc1 4 cc1 0 c1 11 60